Class 5 | CBSE, NCERT & ICSE
In real life, nobody gives you a sum like "245 + 378". Instead, you face situations: "If a train ticket from Delhi to Jaipur costs ₹245 and the return ticket costs ₹378, how much do both tickets cost together?" Word problems are where maths meets real life. They teach you to think, reason, and apply what you've learned.
In Class 5, word problems become more challenging. They often need two or more steps and combine concepts from different chapters — fractions with money, percentage with profit-loss, time with speed, area with cost, and more. The key skill is breaking a big problem into smaller steps.
Follow this 6-step method for every word problem:
| Step | Letter | What to Do | Example |
|---|---|---|---|
| 1 | Read | Read the problem carefully, at least twice | Understand the story/situation |
| 2 | Understand | Identify what is given and what is asked | Given: cost, quantity. Find: total cost |
| 3 | Choose | Decide which operation(s) to use | Multiply, then add |
| 4 | Solve | Do the calculations step by step | Show all working |
| 5 | Answer | Write the answer as a complete sentence with units | "Total cost = ₹575" |
| 6 | Check | Verify — does the answer make sense? Use estimation | Is ₹575 reasonable? |
Think About It: The hardest part isn't the calculation — it's understanding what the problem is asking. Read carefully! Look for keywords like "total" (add), "remaining" (subtract), "each" (divide or multiply), "how much more" (subtract), "altogether" (add).
| Operation | Keywords to Look For |
|---|---|
| Addition (+) | total, altogether, sum, combined, in all, both, together, increased by |
| Subtraction (−) | remaining, left, difference, less than, more than, how much more, decreased by, gave away |
| Multiplication (×) | each, per, every, times, groups of, rows of, total (when rate × quantity) |
| Division (÷) | shared equally, divided among, per person, how many groups, split into |
These problems involve buying, selling, calculating totals, giving change, and managing budgets.
Example 1: Meena bought 3 notebooks at ₹45 each and 5 pens at ₹12 each. She gave ₹200 to the shopkeeper. How much change did she get?
Solution:
Step 1: Cost of notebooks = 3 × ₹45 = ₹135
Step 2: Cost of pens = 5 × ₹12 = ₹60
Step 3: Total cost = ₹135 + ₹60 = ₹195
Step 4: Change = ₹200 − ₹195 = ₹5
Example 2: A shopkeeper in Jaipur buys 50 kg of rice at ₹48 per kg and sells it at ₹56 per kg. Find his total profit.
Solution:
Cost Price (total) = 50 × ₹48 = ₹2,400
Selling Price (total) = 50 × ₹56 = ₹2,800
Profit = SP − CP = ₹2,800 − ₹2,400 = ₹400
Example 3: Priya saved ₹1,250 per month for 8 months. She spent ₹4,500 on books and ₹2,800 on a school bag. How much money does she have left?
Solution:
Total savings = 8 × ₹1,250 = ₹10,000
Total spent = ₹4,500 + ₹2,800 = ₹7,300
Money left = ₹10,000 − ₹7,300 = ₹2,700
Example 4: Ravi had ₹600. He spent 1/3 of it on food and 1/4 of it on a book. How much money is left?
Solution:
Spent on food = 1/3 × ₹600 = ₹200
Spent on book = 1/4 × ₹600 = ₹150
Total spent = ₹200 + ₹150 = ₹350
Money left = ₹600 − ₹350 = ₹250
Example 5: A rope is 12.5 m long. If 3.75 m is cut off, and the remaining rope is divided into 5 equal pieces, what is the length of each piece?
Solution:
Remaining rope = 12.5 − 3.75 = 8.75 m
Length of each piece = 8.75 ÷ 5 = 1.75 m
Example 6: A tank is 3/5 full. It contains 240 litres of water. What is the full capacity of the tank?
Solution:
3/5 of capacity = 240 litres
1/5 of capacity = 240 ÷ 3 = 80 litres
Full capacity (5/5) = 80 × 5 = 400 litres
Example 7: In a school of 800 students, 45% are girls. How many boys are there?
Solution:
Percentage of boys = 100% − 45% = 55%
Number of boys = 55% of 800 = (55/100) × 800 = 440 boys
Example 8: Arjun scored 72 out of 80 in Maths and 45 out of 50 in Science. In which subject did he score a higher percentage?
Solution:
Maths percentage = (72/80) × 100 = 90%
Science percentage = (45/50) × 100 = 90%
Both are equal at 90%
Example 9: A shirt costs ₹800. The shop gives a 15% discount. What is the selling price?
Solution:
Discount = 15% of ₹800 = (15/100) × 800 = ₹120
Selling price = ₹800 − ₹120 = ₹680
Example 10: A bus travels from Pune to Mumbai (150 km) in 3 hours. It then travels from Mumbai to Surat (280 km) in 4 hours. What is the average speed for the entire journey?
Solution:
Total distance = 150 + 280 = 430 km
Total time = 3 + 4 = 7 hours
Average speed = 430 ÷ 7 = 61.4 km/h (approx.)
Example 11: Sita leaves home at 8:45 AM and reaches school at 9:20 AM. If the school is 2.1 km from her home, what is her average walking speed?
Solution:
Time taken = 9:20 − 8:45 = 35 minutes = 35/60 hours = 7/12 hours
Speed = Distance ÷ Time = 2.1 ÷ (7/12) = 2.1 × 12/7 = 25.2/7 = 3.6 km/h
Example 12: A rectangular garden is 25 m long and 18 m wide. A path 2 m wide runs around the garden. Find the area of the path.
Solution:
Outer length = 25 + 2 + 2 = 29 m
Outer width = 18 + 2 + 2 = 22 m
Outer area = 29 × 22 = 638 m²
Inner area (garden) = 25 × 18 = 450 m²
Area of path = 638 − 450 = 188 m²
Example 13: A square room has a perimeter of 48 m. If tiling costs ₹85 per m², find the total cost of tiling the floor.
Solution:
Side of square = 48 ÷ 4 = 12 m
Area = 12 × 12 = 144 m²
Total cost = 144 × ₹85 = ₹12,240
Example 14: Ravi has a rectangular field 120 m long and 80 m wide. He wants to fence it with barbed wire. If fencing costs ₹25 per metre, and he puts 3 rounds of wire, find the total cost.
Solution:
Perimeter = 2 × (120 + 80) = 2 × 200 = 400 m
Total wire needed = 3 × 400 = 1,200 m
Total cost = 1,200 × ₹25 = ₹30,000
Example 15: The average marks of 40 students is 72. Later, 5 more students join with an average of 80. Find the new average of all 45 students.
Solution:
Total marks of 40 students = 40 × 72 = 2,880
Total marks of 5 new students = 5 × 80 = 400
New total = 2,880 + 400 = 3,280
New average = 3,280 ÷ 45 = 72.9 (approx.)
Example 16: In a cricket match, Team India scored 280 runs. Rohit scored 1/4 of the total, Virat scored 30% of the total, and the remaining runs were scored by other players. How many runs did other players score?
Solution:
Rohit's score = 1/4 × 280 = 70 runs
Virat's score = 30% of 280 = (30/100) × 280 = 84 runs
Others' score = 280 − 70 − 84 = 126 runs
Example 17: 12 workers can build a wall in 10 days. How many days will 15 workers take to build the same wall?
Solution:
This is inverse proportion (more workers = less days)
12 workers → 10 days
1 worker → 10 × 12 = 120 days
15 workers → 120 ÷ 15 = 8 days
Example 18: If 5 kg of mangoes cost ₹375, find the cost of 8 kg of mangoes.
Solution:
Cost of 5 kg = ₹375
Cost of 1 kg = ₹375 ÷ 5 = ₹75
Cost of 8 kg = ₹75 × 8 = ₹600
| Word/Phrase | Meaning / Operation |
|---|---|
| Altogether / In all / Total | Addition |
| Remaining / Left over / Balance | Subtraction |
| Each / Per / Every / Times | Multiplication |
| Shared equally / Distributed / Per person | Division |
| How much more / How much less | Subtraction (comparison) |
| Fraction of | Multiply by fraction |
| Percentage of | Multiply by percentage/100 |
| Profit / Loss | SP − CP or CP − SP |
| Average | Sum ÷ Number |
| Speed | Distance ÷ Time |
Finished learning? Now test what you know!