Word Problems — Multi-Concept

Mathematics

Class 5 | CBSE, NCERT & ICSE

Learning Objectives

Introduction — Why Word Problems?

In real life, nobody gives you a sum like "245 + 378". Instead, you face situations: "If a train ticket from Delhi to Jaipur costs ₹245 and the return ticket costs ₹378, how much do both tickets cost together?" Word problems are where maths meets real life. They teach you to think, reason, and apply what you've learned.

In Class 5, word problems become more challenging. They often need two or more steps and combine concepts from different chapters — fractions with money, percentage with profit-loss, time with speed, area with cost, and more. The key skill is breaking a big problem into smaller steps.

Image needed: A visual showing the journey from a word problem to solution: a paragraph of text → identifying key info → choosing operation → calculating → writing the answer. Use Indian school children thinking with thought bubbles.
Style: Flat illustration, step-by-step visual, colourful
Size: 750×350px

The RUCSAC Strategy for Solving Word Problems

Follow this 6-step method for every word problem:

StepLetterWhat to DoExample
1ReadRead the problem carefully, at least twiceUnderstand the story/situation
2UnderstandIdentify what is given and what is askedGiven: cost, quantity. Find: total cost
3ChooseDecide which operation(s) to useMultiply, then add
4SolveDo the calculations step by stepShow all working
5AnswerWrite the answer as a complete sentence with units"Total cost = ₹575"
6CheckVerify — does the answer make sense? Use estimationIs ₹575 reasonable?

Think About It: The hardest part isn't the calculation — it's understanding what the problem is asking. Read carefully! Look for keywords like "total" (add), "remaining" (subtract), "each" (divide or multiply), "how much more" (subtract), "altogether" (add).

Keywords That Help You Choose the Operation

OperationKeywords to Look For
Addition (+)total, altogether, sum, combined, in all, both, together, increased by
Subtraction (−)remaining, left, difference, less than, more than, how much more, decreased by, gave away
Multiplication (×)each, per, every, times, groups of, rows of, total (when rate × quantity)
Division (÷)shared equally, divided among, per person, how many groups, split into

Category 1: Money and Shopping Problems

These problems involve buying, selling, calculating totals, giving change, and managing budgets.

Example 1: Meena bought 3 notebooks at ₹45 each and 5 pens at ₹12 each. She gave ₹200 to the shopkeeper. How much change did she get?

Solution:

Step 1: Cost of notebooks = 3 × ₹45 = ₹135

Step 2: Cost of pens = 5 × ₹12 = ₹60

Step 3: Total cost = ₹135 + ₹60 = ₹195

Step 4: Change = ₹200 − ₹195 = ₹5

Example 2: A shopkeeper in Jaipur buys 50 kg of rice at ₹48 per kg and sells it at ₹56 per kg. Find his total profit.

Solution:

Cost Price (total) = 50 × ₹48 = ₹2,400

Selling Price (total) = 50 × ₹56 = ₹2,800

Profit = SP − CP = ₹2,800 − ₹2,400 = ₹400

Example 3: Priya saved ₹1,250 per month for 8 months. She spent ₹4,500 on books and ₹2,800 on a school bag. How much money does she have left?

Solution:

Total savings = 8 × ₹1,250 = ₹10,000

Total spent = ₹4,500 + ₹2,800 = ₹7,300

Money left = ₹10,000 − ₹7,300 = ₹2,700

Category 2: Fractions and Decimals

Example 4: Ravi had ₹600. He spent 1/3 of it on food and 1/4 of it on a book. How much money is left?

Solution:

Spent on food = 1/3 × ₹600 = ₹200

Spent on book = 1/4 × ₹600 = ₹150

Total spent = ₹200 + ₹150 = ₹350

Money left = ₹600 − ₹350 = ₹250

Example 5: A rope is 12.5 m long. If 3.75 m is cut off, and the remaining rope is divided into 5 equal pieces, what is the length of each piece?

Solution:

Remaining rope = 12.5 − 3.75 = 8.75 m

Length of each piece = 8.75 ÷ 5 = 1.75 m

Example 6: A tank is 3/5 full. It contains 240 litres of water. What is the full capacity of the tank?

Solution:

3/5 of capacity = 240 litres

1/5 of capacity = 240 ÷ 3 = 80 litres

Full capacity (5/5) = 80 × 5 = 400 litres

Category 3: Percentage Problems

Example 7: In a school of 800 students, 45% are girls. How many boys are there?

Solution:

Percentage of boys = 100% − 45% = 55%

Number of boys = 55% of 800 = (55/100) × 800 = 440 boys

Example 8: Arjun scored 72 out of 80 in Maths and 45 out of 50 in Science. In which subject did he score a higher percentage?

Solution:

Maths percentage = (72/80) × 100 = 90%

Science percentage = (45/50) × 100 = 90%

Both are equal at 90%

Example 9: A shirt costs ₹800. The shop gives a 15% discount. What is the selling price?

Solution:

Discount = 15% of ₹800 = (15/100) × 800 = ₹120

Selling price = ₹800 − ₹120 = ₹680

Category 4: Time, Speed, and Distance

Example 10: A bus travels from Pune to Mumbai (150 km) in 3 hours. It then travels from Mumbai to Surat (280 km) in 4 hours. What is the average speed for the entire journey?

Solution:

Total distance = 150 + 280 = 430 km

Total time = 3 + 4 = 7 hours

Average speed = 430 ÷ 7 = 61.4 km/h (approx.)

Example 11: Sita leaves home at 8:45 AM and reaches school at 9:20 AM. If the school is 2.1 km from her home, what is her average walking speed?

Solution:

Time taken = 9:20 − 8:45 = 35 minutes = 35/60 hours = 7/12 hours

Speed = Distance ÷ Time = 2.1 ÷ (7/12) = 2.1 × 12/7 = 25.2/7 = 3.6 km/h

Image needed: A visual map showing a bus route from Pune to Mumbai to Surat with distances (150 km, 280 km) and time (3 hrs, 4 hrs) marked on the route. Indian city names with highway markers.
Style: Simple route map with colourful markers, child-friendly
Size: 650×300px

Category 5: Measurement and Geometry

Example 12: A rectangular garden is 25 m long and 18 m wide. A path 2 m wide runs around the garden. Find the area of the path.

Solution:

Outer length = 25 + 2 + 2 = 29 m

Outer width = 18 + 2 + 2 = 22 m

Outer area = 29 × 22 = 638 m²

Inner area (garden) = 25 × 18 = 450 m²

Area of path = 638 − 450 = 188 m²

Example 13: A square room has a perimeter of 48 m. If tiling costs ₹85 per m², find the total cost of tiling the floor.

Solution:

Side of square = 48 ÷ 4 = 12 m

Area = 12 × 12 = 144 m²

Total cost = 144 × ₹85 = ₹12,240

Example 14: Ravi has a rectangular field 120 m long and 80 m wide. He wants to fence it with barbed wire. If fencing costs ₹25 per metre, and he puts 3 rounds of wire, find the total cost.

Solution:

Perimeter = 2 × (120 + 80) = 2 × 200 = 400 m

Total wire needed = 3 × 400 = 1,200 m

Total cost = 1,200 × ₹25 = ₹30,000

Image needed: Diagram of a rectangular garden (25m × 18m) with a 2m path around it. Show inner rectangle (garden) in green and outer path in grey with measurements labelled clearly.
Style: Clean geometric diagram with dimensions, coloured
Size: 550×400px

Category 6: Average and Data Problems

Example 15: The average marks of 40 students is 72. Later, 5 more students join with an average of 80. Find the new average of all 45 students.

Solution:

Total marks of 40 students = 40 × 72 = 2,880

Total marks of 5 new students = 5 × 80 = 400

New total = 2,880 + 400 = 3,280

New average = 3,280 ÷ 45 = 72.9 (approx.)

Example 16: In a cricket match, Team India scored 280 runs. Rohit scored 1/4 of the total, Virat scored 30% of the total, and the remaining runs were scored by other players. How many runs did other players score?

Solution:

Rohit's score = 1/4 × 280 = 70 runs

Virat's score = 30% of 280 = (30/100) × 280 = 84 runs

Others' score = 280 − 70 − 84 = 126 runs

Category 7: Unitary Method Problems

Example 17: 12 workers can build a wall in 10 days. How many days will 15 workers take to build the same wall?

Solution:

This is inverse proportion (more workers = less days)

12 workers → 10 days

1 worker → 10 × 12 = 120 days

15 workers → 120 ÷ 15 = 8 days

Example 18: If 5 kg of mangoes cost ₹375, find the cost of 8 kg of mangoes.

Solution:

Cost of 5 kg = ₹375

Cost of 1 kg = ₹375 ÷ 5 = ₹75

Cost of 8 kg = ₹75 × 8 = ₹600

Key Words

Word/PhraseMeaning / Operation
Altogether / In all / TotalAddition
Remaining / Left over / BalanceSubtraction
Each / Per / Every / TimesMultiplication
Shared equally / Distributed / Per personDivision
How much more / How much lessSubtraction (comparison)
Fraction ofMultiply by fraction
Percentage ofMultiply by percentage/100
Profit / LossSP − CP or CP − SP
AverageSum ÷ Number
SpeedDistance ÷ Time

Tips for Solving Word Problems

  • Always read the problem at least twice before starting
  • Underline the important numbers and what is being asked
  • Draw a picture or diagram if it helps (especially for geometry problems)
  • Break multi-step problems into smaller, simpler steps
  • Always include units in your answer (₹, km, kg, m², etc.)
  • Check: Does your answer make sense? Is it too big or too small?
  • Use estimation to verify — round numbers and check roughly
  • Write "Given", "To Find", and "Solution" clearly for long problems
  • Look for hidden information (e.g., "a dozen" = 12, "a pair" = 2)
  • In multi-step problems, the answer of one step often becomes the input for the next step

Finished learning? Now test what you know!